zoj1151 zoj1295 Word Reversal 字符串的简单处理

Word ReversalTime Limit: 2 Seconds Memory Limit:65536 KB
For each list of words, output a line with each word reversed without changing the order of the words.

This problem contains multiple test cases!

The first line of a multiple input is an integer N, then a blank line followed by N input blocks. Each input block is in the format indicated in the problem description. There is a blank line between input blocks.

The output format consists of N output blocks. There is a blank line between output blocks.

Input

You will be given a number of test cases. The first line contains a positive integer indicating the number of cases to follow. Each case is given on a line containing a list of words separated by one space, and each word contains
only uppercase and lowercase letters.

Output

For each test case, print the output on one line.

Sample Input

1

3

I am happy today

To be or not to be

I want to win the practice contest

Sample Output

I ma yppah yadot

oT eb ro ton ot eb

I tnaw ot niw eht ecitcarp tsetnoc
http://blog.csdn.net/AC_0_summer/article/details/44747401

#include<cstdio>
#include<cstdlib>
#include<iostream>
#include<algorithm>
using namespace std;
char s[500];
void _S()
{
int L=0;
s[L++]=getchar();
while(s[L-1]!='\n'){
if(s[L-1]==' ')
{
for(int i=L-2;i>=0;i--)
putchar(s[i]);
printf(" ");
L=0;
}
s[L++]=getchar();
}
for(int i=L-2;i>=0;i--)
putchar(s[i]);
printf("\n");
return ;
}

int main()
{
int n,T;

scanf("%d",&T);
while(T--){
scanf("%d\n",&n);//过滤换行符
while(n--) _S();
if(T) printf("\n"); //此题容易因为此处PE
}
return 0;
}
zoj1295：
#include<cstdio>
#include<cstdlib>
#include<iostream>
using namespace std;
void _S()
{
char s[71];
int num=0;
char c=getchar();
while(true){
if(c=='\n'){
for(int i=num;i>=1;i--) cout<<s[i];
cout<<endl;
return ;
}
s[++num]=c;
c=getchar();
}
}
int main()
{
int n;
scanf("%d\n",&n);
while(n--)
_S()
return 0;
}

为什么感觉题目没有解释很清楚，让那么多人PE。。。。。。。。。。。

当然本题处理方式有很多，也可以每一行输入后再处理。个人属于习惯单个字符输入的那种（此时要注意过滤换行符什么的）。