The sum of numbers form 0 to n.(20.9.2017)
2017-09-24 19:34
399 查看
#include <stdio.h> int main() { int a,b,sum; printf("输入一个数字: "); scanf("%d",&a); //输入数字a sum = 0; for(b=1;b<=a;b++){ //设置b=1 使用for loop,用b相加,一直加到输入的数字a的数值 sum = sum + b; } printf("%d",sum); }
相关文章推荐
- perfect squares find the least number of perfect square numbers (1, 4, 9, 16, ...) which sum to n
- Define a procedure that takes three numbers as arguments and returns the sum of the squares of the two larger numbers
- Given an integer, return all sequences of numbers that sum to it
- Which Numbers are the Sum of Two Squares?
- The Black Hole of Numbers (strtoint+inttostr+sort)
- The reversed sum of two reversed numbers
- How to workaround the IE default behavior of re-posting the entire form when pressing "刷新"(or F5)
- Problem 21 of Evaluate the sum of all the amicable numbers under 10000.
- How to change the background color of form using C++ - 如何用C++改变窗体的颜色
- How to get the value of a form element : check box and radio button
- How to get the query statement of LOV in Oracle Form
- The color chooser class, you could slide the scroll bars to get the specific numbers of the color
- Print the numbers of form 2^i.5^j in increasing order -- Google
- More than one way to get the max of 3 numbers.
- No configuration found for the specified action: '/sum' in namespace: ''.Form action defaulting to '
- Find the maximum of the three numbers(Take this opportunity to review the sorting algorithm)
- How to programmatically change the default view of an InfoPath form
- To find sum of two numbers without using any operator. Only use of printf() is allowed.
- URAL 1206 Sum of Digits of the Sum of Numbers
- Sum of numbers from 0 to N -- 7 kyu