python将list转为tuple

此博客提供一种将list转为tuple，并提取相应的矩阵的方法，代码如下：

dates = pd.date_range('20130101', periods=6)
df = pd.DataFrame(np.random.randn(6,4), index=dates, columns=list('ABCD'))
print df
tf=tuple(df.values)
m=np.random.randn(6,4)
for index,i in enumerate(tf):
m[index]=i
print m[:2,:-1]

运行结果：

A B C D

2013-01-01 -0.141409 -0.730154 1.575341 1.574466

2013-01-02 1.467078 0.407789 0.037842 0.121589

2013-01-03 -0.584768 1.303740 0.582591 0.798636

2013-01-04 -1.270843 0.251929 0.375151 -1.338465

2013-01-05 0.158676 -1.539456 -0.329063 -0.149361

2013-01-06 -0.732903 1.272572 -0.340342 0.414401

[[-0.141409 -0.73015353 1.57534091]

[ 1.46707818 0.40778942 0.03784234]]