poj 3069 Saruman's Army
2017-09-23 10:28
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题目:
贪心算法,先对x[i]从小到大排序,然后从x[0]开始遍历,找到x[0]+R能覆盖的最远的点i,找到x[i]+R能覆盖的最远的点l。再以l为起点循环上述过程
AC情况:
代码:
贪心算法,先对x[i]从小到大排序,然后从x[0]开始遍历,找到x[0]+R能覆盖的最远的点i,找到x[i]+R能覆盖的最远的点l。再以l为起点循环上述过程
AC情况:
代码:
#include<iostream> #include<algorithm> using namespace std; int x[1005]; int main() { int R, N,cnt; while (scanf("%d%d",&R,&N)){ if (R == N&&N == -1) break; cnt = 0; for (int i = 0; i < N; i++) scanf("%d", &x[i]); sort(x, x + N); for (int i=0; i < N;) { int t = i; cnt++; while (x[t] + R >= x[i++]); i=t = i-2; while (x[t] + R >= x[i++]); i--; } printf("%d\n", cnt); } return 0; }
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