566. Reshape the Matrix
2017-09-21 23:48
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题目
566. Reshape the Matrix解题思路
判断一下reshape后的矩阵里面的元素数量是否与原来一致,如果不一致则返回原矩阵,如果一致则用一个一维数组把原矩阵的元素储存再重新reshape具体代码
class Solution { public: vector<vector<int>> matrixReshape(vector<vector<int>>& nums, int r, int c) { int origin_r = nums.size(), origin_c = 0; if (origin_r) origin_c = nums[0].size(); if (origin_r * origin_c != r * c) return nums; vector<int> tmp; for (int i = 0; i < origin_r; i++) for (int j = 0; j < origin_c; j++) { tmp.push_back(nums[i][j]); } vector<vector<int>> nums_t; for (int i = 0; i < r; i++) { vector<int> tmp_t; for (int j = 0; j < c; j++) { tmp_t.push_back(tmp[i * c + j]); } nums_t.push_back(tmp_t); } return nums_t; } };
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