poj 1611 The Suspects(并查集)
2017-09-19 19:20
423 查看
The Suspects
Time Limit: 1000MS Memory Limit: 20000KTotal Submissions: 42354 Accepted: 20430
Description
Severe acute respiratory syndrome (SARS), an atypical pneumonia of unknown aetiology, was recognized as a global threat in mid-March 2003. To minimize transmission to others, the best strategy is to separate the suspects from others.
In the Not-Spreading-Your-Sickness University (NSYSU), there are many student groups. Students in the same group intercommunicate with each other frequently, and a student may join several groups. To prevent the possible transmissions of SARS, the NSYSU collects the member lists of all student groups, and makes the following rule in their standard operation procedure (SOP).
Once a member in a group is a suspect, all members in the group are suspects.
However, they find that it is not easy to identify all the suspects when a student is recognized as a suspect. Your job is to write a program which finds all the suspects.
Input
The input file contains several cases. Each test case begins with two integers n and m in a line, where n is the number of students, and m is the number of groups. You may assume that 0 < n <= 30000 and 0 <= m <= 500. Every student is numbered by a unique integer between 0 and n−1, and initially student 0 is recognized as a suspect in all the cases. This line is followed by m member lists of the groups, one line per group. Each line begins with an integer k by itself representing the number of members in the group. Following the number of members, there are k integers representing the students in this group. All the integers in a line are separated by at least one space.
A case with n = 0 and m = 0 indicates the end of the input, and need not be processed.
Output
For each case, output the number of suspects in one line.
Sample Input
100 4
2 1 2
5 10 13 11 12 14
2 0 1
2 99 2
200 2
1 5
5 1 2 3 4 5
1 0
0 0
Sample Output
4
1
1
初始状态下是标记为0的那个人得病,当得病的人参加的社团,社团里的人都会得病,求出有多少人得病。
#include <iostream> #include <cstdio> #include <cstring> #include <algorithm> using namespace std; #define N 31111 int p ; int fnd( int x ){ return p[x] = p[x] == x ? x : fnd( p[x] ); } void unit( int x, int y ) { int u = fnd( x ); int v = fnd( y ); if( u != v ){ p[u] = y; } } int main() { //freopen( "in.txt", "r", stdin ); int n, m, k, _stu, stu, num, sum; while( scanf( "%d%d", &n, &m ) != EOF ){ if( n == 0 && m == 0 ) break; for( int i = 0 ; i < n ; i ++ ){ p[i] = i; } for( int i = 0 ; i < m ; i ++ ){ scanf( "%d", &k ); _stu = -1; for( int j = 0 ; j < k ; j ++ ){ scanf( "%d", &stu ); if( _stu != -1 ){ if( fnd( _stu ) != fnd( stu ) ) unit( _stu, stu ); } _stu = stu; } } sum = 0; num = fnd( 0 );//cout<<num<<endl; for( int i = 0 ; i < n ; i ++ ){ //cout<<fnd( i )<<endl; if( fnd( i ) == num ) sum ++; } cout<<sum<<endl; } return 0; }
相关文章推荐
- poj 1611 The Suspects(并查集)
- POJ 1611 The Suspects 并查集
- POJ 1611 The Suspects:并查集
- POJ-1611-The Suspects (简单并查集!)
- POJ 1611 The Suspects(并查集)
- POJ-1611-The Suspects(并查集)
- poj 1611 The Suspects(并查集)
- POJ 1611 The Suspects(带权并查集)
- POJ - 1611 The Suspects (并查集 查找同一集合元素)
- POJ 1611 The Suspects (并查集)
- POJ ~ 1611 ~ The Suspects (并查集)
- poj 1611 The Suspects(并查集)
- POJ - 1611 The Suspects(并查集)
- POJ训练计划1611_The Suspects(并查集)
- POJ1611 The Suspects (并查集)
- poj1611 The Suspects(并查集)
- poj-1611-The Suspects(并查集)
- POJ 1611 The Suspects(并查集)
- POJ 1611 The Suspects (并查集,简单)
- POJ 1611 The Suspects(并查集)