Cutting Sticks UVA - 10003
2017-09-13 20:41
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紫书上面思路已经描述得很清楚了,唯一注意切点下标仅仅相差1的时候是不需要截断的,这个时候要记得将相应的数组元素的值初始化为0,具体实现见如下代码:
#include<iostream>
#include<vector>
#include<string>
#include<set>
#include<stack>
#include<queue>
#include<map>
#include<algorithm>
#include<cmath>
#include<iomanip>
#include<cstring>
#include<sstream>
#include<cstdio>
#include<deque>
using namespace std;
int l, n;
int main(){
while (cin >> l&&l){
cin >> n;
int length[1010];
for (int i = 1; i <= n; i++) cin >> length[i];
length[0] = 0;
length[n + 1] = l;
int result[500][500];
for (int i = 0; i < 499; i++) result[i][i + 1] = 0;
for (int i = n - 1; i >= 0; i--){
for (int j = i + 2; j <= n + 1; j++){
result[i][j] = 1 << 20;
for (int k = i + 1; k < j; k++){
result[i][j] = min(result[i][j],
result[i][k] + result[k][j] + length[j] - length[i]);
}
}
}
cout <<"The minimum cutting is "<<result[0][n+1]<<".\n";
}
return 0;
}
#include<iostream>
#include<vector>
#include<string>
#include<set>
#include<stack>
#include<queue>
#include<map>
#include<algorithm>
#include<cmath>
#include<iomanip>
#include<cstring>
#include<sstream>
#include<cstdio>
#include<deque>
using namespace std;
int l, n;
int main(){
while (cin >> l&&l){
cin >> n;
int length[1010];
for (int i = 1; i <= n; i++) cin >> length[i];
length[0] = 0;
length[n + 1] = l;
int result[500][500];
for (int i = 0; i < 499; i++) result[i][i + 1] = 0;
for (int i = n - 1; i >= 0; i--){
for (int j = i + 2; j <= n + 1; j++){
result[i][j] = 1 << 20;
for (int k = i + 1; k < j; k++){
result[i][j] = min(result[i][j],
result[i][k] + result[k][j] + length[j] - length[i]);
}
}
}
cout <<"The minimum cutting is "<<result[0][n+1]<<".\n";
}
return 0;
}
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