leetcode刷题日记—— Longest Continuous Increasing Subsequence
2017-09-12 10:51
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Given an unsorted array of integers, find the length of longest
Example 1:
Example 2:
Note:Length of the array will not exceed 10,000
代码如下:
continuousincreasing subsequence.
Example 1:
Input: [1,3,5,4,7] Output: 3 Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4.
Example 2:
Input: [2,2,2,2,2] Output: 1 Explanation: The longest continuous increasing subsequence is [2], its length is 1.
Note:Length of the array will not exceed 10,000
代码如下:
class Solution { public int findLengthOfLCIS(int[] nums) { int res = 0, cnt = 0; for(int i = 0; i < nums.length; i++){ if(i == 0 || nums[i-1] < nums[i]) res = Math.max(res, ++cnt); else cnt = 1; } return res; } }
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