【PAT甲级】1036. Boys vs Girls (25)——JAVA实现
2017-09-11 01:01
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This time you are asked to tell the difference between the lowest grade of all the male students and the highest grade of all the female students.
Input Specification:
Each input file contains one test case. Each case contains a positive integer N, followed by N lines of student information. Each line contains a student’s name, gender, ID and grade, separated by a space, where name and ID are strings of no more than 10 characters with no space, gender is either F (female) or M (male), and grade is an integer between 0 and 100. It is guaranteed that all the grades are distinct.
Output Specification:
For each test case, output in 3 lines. The first line gives the name and ID of the female student with the highest grade, and the second line gives that of the male student with the lowest grade. The third line gives the difference gradeF-gradeM. If one such kind of student is missing, output “Absent” in the corresponding line, and output “NA” in the third line instead.
Sample Input 1:
3
Joe M Math990112 89
Mike M CS991301 100
Mary F EE990830 95
Sample Output 1:
Mary EE990830
Joe Math990112
6
Sample Input 2:
1
Jean M AA980920 60
Sample Output 2:
Absent
Jean AA980920
NA
题目大意:给定几个学生的姓名、性别、id和成绩,分别输出女生中成绩最好的学生的姓名和id以及男生中成绩最差的学生的姓名和id,并输出两者成绩之差(女减男),如果输入的数据缺少男或女同学的信息,则在缺的那行打印“Absent”来代替,最后行打印“NA”。
分析:该题较简单,方法很多,就提供一种使用Comparable接口的方法。
Input Specification:
Each input file contains one test case. Each case contains a positive integer N, followed by N lines of student information. Each line contains a student’s name, gender, ID and grade, separated by a space, where name and ID are strings of no more than 10 characters with no space, gender is either F (female) or M (male), and grade is an integer between 0 and 100. It is guaranteed that all the grades are distinct.
Output Specification:
For each test case, output in 3 lines. The first line gives the name and ID of the female student with the highest grade, and the second line gives that of the male student with the lowest grade. The third line gives the difference gradeF-gradeM. If one such kind of student is missing, output “Absent” in the corresponding line, and output “NA” in the third line instead.
Sample Input 1:
3
Joe M Math990112 89
Mike M CS991301 100
Mary F EE990830 95
Sample Output 1:
Mary EE990830
Joe Math990112
6
Sample Input 2:
1
Jean M AA980920 60
Sample Output 2:
Absent
Jean AA980920
NA
题目大意:给定几个学生的姓名、性别、id和成绩,分别输出女生中成绩最好的学生的姓名和id以及男生中成绩最差的学生的姓名和id,并输出两者成绩之差(女减男),如果输入的数据缺少男或女同学的信息,则在缺的那行打印“Absent”来代替,最后行打印“NA”。
分析:该题较简单,方法很多,就提供一种使用Comparable接口的方法。
import java.util.ArrayList; import java.util.Collections; import java.util.Scanner; class Student implements Comparable{ String name; boolean man; String id; int grade; public Student(){ } public Student(String name, boolean man, String id, int grade) { super(); this.name = name; this.man = man; this.id = id; this.grade = grade; } @Override public int compareTo(Object o) { // TODO Auto-generated method stub Student stu = (Student)o; return this.grade>stu.grade? 1:(this.grade==stu.grade?0:-1); } } public class Main { public static void main(String[] args) { Scanner input = new Scanner(System.in); boolean flag = false; int n,grade; Student stu1=new Student(),stu2=new Student(); String name,id,gender; ArrayList<Student> list1 = new ArrayList<Student>();//用来存放男生信息 ArrayList<Student> list2 = new ArrayList<Student>();//用来存放女生信息 n = input.nextInt(); for(int i=0;i<n;i++){ name = input.next(); gender = input.next(); id = input.next(); grade = input.nextInt(); if(gender.equals("M")) list1.add(new Student(name,true,id,grade)); else list2.add(new Student(name,false,id,grade)); } Collections.sort(list1); Collections.sort(list2); if(list2.size()==0){ flag = true; System.out.println("Absent"); } else{ stu2 = list2.get(list2.size()-1);//女生找成绩最好的,即排序后最后一个元素 System.out.println(stu2.name + " " + stu2.id); } if(list1.size()==0){ flag = true; System.out.println("Absent"); }else{ stu1 = list1.get(0);//男生找成绩最差的,即排序后第一个元素 System.out.println(stu1.name + " " + stu1.id); } if(flag){ System.out.println("NA"); }else{ System.out.println(stu2.grade-stu1.grade); } } }
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