[LeetCode] 051: Median of Two Sorted Arrays
2017-09-10 20:49
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[Problem]
There are two sorted arrays A and B of size m and n respectively. Find
the median of the two sorted arrays. The overall run time complexity
should be O(log (m+n)).
[Solution]
There are two sorted arrays A and B of size m and n respectively. Find
the median of the two sorted arrays. The overall run time complexity
should be O(log (m+n)).
[Solution]
class Solution{ public: // find the kth element of two sorted arrays double findKth(int *A, int m, int *B, int n, int k){ // invalid k if(k <= 0 || k > m + n)return 0; // because i=min(k/2, m), j=k-i, so i <= j, we should make sure m <= n if(m > n)return findKth(B, n, A, m, k); // either A or B is empty if(m == 0)return B[k-1]; if(n == 0)return A[k-1]; // the first of the two sorted arrays if(k == 1)return min(A[0], B[0]); // binary search int i = min(k/2, m), j = k - i; if(A[i-1] < B[j-1]){ return findKth(A+i, m-i, B, n, k-i); } else if(A[i-1] > B[j-1]){ return findKth(A, m, B+j, n-j, k-j); } else{ return A[i-1]; } } // find the median of two sorted arrays double findMedianSortedArrays(int A[], int m, int B[], int n){ // Start typing your C/C++ solution below // DO NOT write int main() function if((m+n) % 2 == 0){ return (findKth(A, m, B, n, (m+n)/2) + findKth(A, m, B, n, (m+n)/2+1)) / 2; } else{ return findKth(A, m, B, n, (m+n)/2+1); } } };说明:版权所有,转载请注明出处。Coder007的博客
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