LeetCode 240. Search a 2D Matrix II
2017-09-09 15:55
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原题地址
题目内容
题目分析
这个矩阵从左到右逐渐增大,从上到下也是逐渐增大的。先从最右列第一个数开始比较,如果target大于它,说明target在这一列,否则往左查找,比较左边一列第一个数,以此类推。 确定列数后开始向下寻找行数即可,如果找不到则返回结果fasle。
代码实现
class Solution { public: bool searchMatrix(vector<vector<int>>& matrix, int target) { if(matrix.size() == 0){ return false; } int row = matrix.size(); int col = matrix[0].size(); int i = 0,j = col-1; while(i < row && j >= 0){ if(matrix[i][j] == target) return true; else if(matrix[i][j] > target){ j--; }else i++; } return false; } };
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