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E - New Year and North Pole CodeForces - 750B(状态处理下就好了)

2017-09-08 16:13 459 查看
In this problem we assume the Earth to be a completely round ball and its surface a perfect sphere. The length of the equator and any meridian is considered to be exactly
40 000 kilometers. Thus, travelling from North Pole to South Pole or vice versa takes exactly
20 000 kilometers.

Limak, a polar bear, lives on the North Pole. Close to the New Year, he helps somebody with delivering packages all around the world. Instead of coordinates of places to visit, Limak got a description how he should move, assuming that he starts from the
North Pole. The description consists of n parts. In the
i-th part of his journey, Limak should move
ti kilometers in the direction represented by a string
diri that is one of: "North", "South", "West", "East".

Limak isn’t sure whether the description is valid. You must help him to check the following conditions:

If at any moment of time (before any of the instructions or while performing one of them) Limak is on the North Pole, he can move only to the South.

If at any moment of time (before any of the instructions or while performing one of them) Limak is on the South Pole, he can move only to the North.

The journey must end on the North Pole.
Check if the above conditions are satisfied and print "YES" or "NO" on a single line.

Input

The first line of the input contains a single integer n (1 ≤ n ≤ 50).

The i-th of next
n lines contains an integer ti and a string
diri (1 ≤ ti ≤ 106,


) — the length and the direction of the
i-th part of the journey, according to the description Limak got.

Output

Print "YES" if the description satisfies the three conditions, otherwise print "NO", both without the quotes.

Example

Input
5
7500 South
10000 East
3500 North
4444 West
4000 North


Output
YES


Input
2
15000 South
4000 East


Output
NO


Input
5
20000 South
1000 North
1000000 West
9000 North
10000 North


Output
YES


Input
3
20000 South
10 East
20000 North


Output
NO


Input
2
1000 North
1000 South


Output
NO


Input
4
50 South
50 North
15000 South
15000 North


Output
YES


Note

Drawings below show how Limak's journey would look like in first two samples. In the second sample the answer is "NO" because he doesn't end on the North Pole.



状态处理下就ok

代码:

#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<cstdlib>
#include<map>
using namespace std;
int main()
{
int n;
int level[100];
char dir[100][50];
int kk= 20000;//表示此刻在北极
scanf("%d",&n);
int tai=1;//表示此刻的状态在北极
// 1表示北 2表示南 3表示在中间
for(int i=1;i<=n;i++)
scanf("%d %s",&level[i],dir[i]);
for(int i=1;i<=n;i++)
{
if(dir[i][0]=='N')//1
{
if(tai==1)
{
printf("NO\n");
return 0;
}
else
{
kk=kk+level[i];
if(kk>20000)
{
printf("NO\n");
return 0;
}
}
if(kk==20000) tai=1;
else if(kk==0) tai=2;
else if(kk>0&&kk<20000) tai=3;
}
else if(dir[i][0]=='S')//2
{
if(tai==2)
{
printf("NO\n");
return 0;
}
else
{
kk=kk-level[i];
if(kk<0)
{
printf("NO\n");
return 0;
}
}
if(kk==20000) tai=1;
else if(kk==0) tai=2;
else if(kk>0&&kk<20000) tai=3;
}
else if(dir[i][0]=='E'||dir[i][0]=='W')
{
if(tai==1||tai==2)
{
printf("NO\n");
return 0;
}
}
}
if(tai==1)
printf("YES\n");
else
printf("NO\n");
return 0;
}
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