The kth great number (优先队列)

Xiao Ming and Xiao Bao are playing a simple Numbers game. In a round Xiao Ming can choose to write down a number, or ask Xiao Bao what the kth great number is. Because the number written by Xiao Ming is too much, Xiao Bao is feeling giddy. Now, try to help Xiao Bao.

Input

There are several test cases. For each test case, the first line of input contains two positive integer n, k. Then n lines follow. If Xiao Ming choose to write down a number, there will be an ” I” followed by a number that Xiao Ming will write down. If Xiao Ming choose to ask Xiao Bao, there will be a “Q”, then you need to output the kth great number.

Output

The output consists of one integer representing the largest number of islands that all lie on one line.

Sample Input

8 3

I 1

I 2

I 3

Q

I 5

Q

I 4

Q

Sample Output

1

2

3

[分析]

优先队列做。

不断push数字，如果size>k就pop，保持队列里面是当前最大的k个数。

所以只要在Q的时候输出top就可以了。

需要注意的是不要使用

priority_queue  <int，vector<int>,greater<int>>q;

实测会超时。

重载<号，时间124过的。

[代码]

#include<cstdio>
#include<queue>
#include<vector>
#include<functional>
using namespace std;

struct S
{
int num;
friend bool operator<(S aa,S bb)
{
return aa.num>bb.num;
}
}node;

int main()
{
int n,k,x;
char a[5];
while(scanf("%d%d",&n,&k)!=EOF)
{
priority_queue<S>q;
while(n--)
{
scanf("%s",a);
if(a[0]=='I')
{
scanf("%d",&x);
node.num=x;
q.push(node);
if(q.size()>k)q.pop();
}
else
{
printf("%d\n",q.top());
}
}
}
return 0;
}