Integer Break问题及解法

问题描述：

Given a positive integer n, break it into the sum of at least two positive integers and maximize the product of those integers. Return the maximum product you can get.

示例：

given n = 2, return 1 (2 = 1 + 1); given n = 10, return 36 (10 = 3 + 3 + 4).

Note: You may assume that n is not less than 2 and not larger than 58.
问题分析：

通过分析发现对于n来说，它的最大乘积dp
是 dp[i] * (n - i) 或 i * (n - i) 中最大的那个， (1<= i <= n - 1).

过程详见代码：

class Solution {
public:
int integerBreak(int n) {
vector<int> dp(n + 1, 1);
for (int i = 2; i <= n; i++)
{
for (int j = 1; j < i; j++)
dp[i] = max(dp[i],max(dp[j] * (i - j), j * (i - j)));
}
return dp
;
}
};