633. Sum of Square Numbers

题目：

Given a non-negative integer 

c

, your task is to decide whether there're two integers 

a

 and 

b

 such
that a2 + b2 = c.

Example 1:

Input: 5
Output: True
Explanation: 1 * 1 + 2 * 2 = 5

Example 2:

Input: 3
Output: False

思路：
本题思路是真的简单，只需要循环遍历0-sqrt(c)的整数，判断是否存在符合要求的两个整数。

代码：

class Solution {
public:
bool judgeSquareSum(int c) {
for(int a=0;a<=sqrt(c);a++)
{
if(sqrt(c-a*a)-int(sqrt(c-a*a))==0.0)
return true;
}
return false;
}
};