luogu1089【2004提高】津津的储蓄计划(模拟)

#include<cstdio>
int a,b,s=0,n,ans=0,i,flag=0;
int main(){
//freopen("a.in","r",stdin);
for(i=1;i<=12;i++){
scanf("%d",&a);
b=300+s-a;
if(b<0) {
flag=1;break;}
else {
n=b/100;
ans=ans+n;
s=b-n*100;
}
}
if(flag==1) printf("-%d",i);
else printf("%d",ans=ans*120+s);
return 0;
}