1002. A+B for Polynomials (25)
2017-08-22 21:00
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memset的头文件是<string.h>
This time, you are supposed to find A+B where A and B are two polynomials.
Input
Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 ... NK aNK, where
K is the number of nonzero terms in the polynomial, Ni and aNi (i=1, 2, ..., K) are the exponents and coefficients, respectively. It is given that 1 <= K <= 10,0 <= NK < ... < N2 < N1 <=1000.
Output
For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.
Sample Input
Sample Output
This time, you are supposed to find A+B where A and B are two polynomials.
Input
Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 ... NK aNK, where
K is the number of nonzero terms in the polynomial, Ni and aNi (i=1, 2, ..., K) are the exponents and coefficients, respectively. It is given that 1 <= K <= 10,0 <= NK < ... < N2 < N1 <=1000.
Output
For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.
Sample Input
2 1 2.4 0 3.2 2 2 1.5 1 0.5
Sample Output
3 2 1.5 1 2.9 0 3.2
#include<iostream> #include<string.h> #include<iomanip> using namespace std; int main() { int k1, k2, n; float arry[1001], an; memset(arry, 0, sizeof(arry)); cin >> k1; int count = 0, maxn = 0; for (int i = 0; i < k1; i++) { cin >> n >> an; maxn = maxn > n ? maxn : n; arry = an; } cin >> k2; for (int i = 0; i < k2; i++) { cin >> n >> an; maxn = maxn > n ? maxn : n; arry += an; } for (int i = maxn; i >= 0; i--) if (arry[i] != 0) count++; cout << count; for (int i = maxn; i >= 0; i--) { if (arry[i] != 0) cout << " " << i << " " << setiosflags(ios::fixed) << setprecision(1) << arry[i]; } return 0; }
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