文章标题
2017-08-22 13:26
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f(x)=⎧⎩⎨⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪∫x0sin(x)−−−−−√3dx(x>1)sin(x)−−−−−√3+2x(0≤x≤1)x(−1≤x<0)x2(x<−1)
F($bln,0)==(1+5√2)$bln,0−(1−5√2)$bln,05√$blm000,0
F($bln,0)==(1+5√2)$bln,0−(1−5√2)$bln,05√$blm000,0