[leetcode]46. Permutations@Java解题报告
2017-08-19 10:34
483 查看
https://leetcode.com/problems/permutations/description/
Given a collection of distinct numbers, return all possible permutations.
For example,
package go.jacob.day819;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
/**
* 46. Permutations
* @author Jacob
* 题意:求数组的全排列
*/
public class Demo1 {
List<List<Integer>> res;
public List<List<Integer>> permute(int[] nums) {
res = new ArrayList<List<Integer>>();
if (nums == null || nums.length < 1)
return res;
//对数组元素进行从小到大排序
Arrays.sort(nums);
ArrayList<Integer> list = new ArrayList<Integer>();
solve(list, nums);
return res;
}
private void solve(ArrayList<Integer> list, int[] nums) {
if (list.size() == nums.length) {
res.add(new ArrayList<Integer>(list));
return;
}
for (int i = 0; i < nums.length; i++) {
if (!list.contains(nums[i])) {
list.add(nums[i]);
solve(list, nums);
list.remove(list.size() - 1);
}
}
}
}
Given a collection of distinct numbers, return all possible permutations.
For example,
[1,2,3]have the following permutations:
[ [1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2], [3,2,1] ]
package go.jacob.day819;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
/**
* 46. Permutations
* @author Jacob
* 题意:求数组的全排列
*/
public class Demo1 {
List<List<Integer>> res;
public List<List<Integer>> permute(int[] nums) {
res = new ArrayList<List<Integer>>();
if (nums == null || nums.length < 1)
return res;
//对数组元素进行从小到大排序
Arrays.sort(nums);
ArrayList<Integer> list = new ArrayList<Integer>();
solve(list, nums);
return res;
}
private void solve(ArrayList<Integer> list, int[] nums) {
if (list.size() == nums.length) {
res.add(new ArrayList<Integer>(list));
return;
}
for (int i = 0; i < nums.length; i++) {
if (!list.contains(nums[i])) {
list.add(nums[i]);
solve(list, nums);
list.remove(list.size() - 1);
}
}
}
}
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