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Python 边做边学 8.4 工具类--HTML解析工具(HtmlSoupUtil)

2017-08-18 15:14 661 查看
媳妇给我买衣服,我说:”之前我都是两件衬衫过夏天的~”

她没有说话,用眼神表达了鄙视…

原文连接:http://blog.csdn.net/tomorrow13210073213/article/details/77370291

基础工具

java里有“jsoup”解析html;python里有“Beautiful Soup”;如何寻找节点,如何获得节点属性/内容,用法大同小异;关于“Beautiful Soup”的具体用法不再详述,参考如下:

http://cuiqingcai.com/1319.html

https://www.crummy.com/software/BeautifulSoup/bs4/doc/index.zh.html

进一步封装

为了使用方便,基于“Beautiful Soup”进行了进一步封装,使用更方便;封装之前,先确定我们需要哪几个方法:

1. 通过ID获取元素;

2. 通过class获取元素;

3. 通过name获取元素;

4. 通过标签名获取元素

5. 获取元素内部文本;

Talk is cheap. Show me the code

# 通过标签名和class获取第一个元素
def get_one_by_class(soup, ele_name, class_name):
if soup is None:
return None
eles = soup.find_all(ele_name, {"class": class_name}, limit=1)
if eles is None or len(eles) == 0:
return None
return eles[0]

# 通过标签名和class获取所有元素
def get_by_class(soup, ele_name, class_name):
if soup is None:
return None
eles = soup.find_all(ele_name, {"class": class_name})
if eles is None or len(eles) == 0:
return None
return eles

# 通过标签名和id获取第一个元素
def get_one_by_id(soup, ele_name, id_name):
if soup is None:
return None
eles = soup.find_all(ele_name, {"id": id_name}, limit=1)
if eles is None or len(eles) == 0:
return None
return eles[0]

# 通过标签名和id获取所有元素
def get_by_id(soup, ele_name, id_name):
if soup is None:
return None
eles = soup.find_all(ele_name, {"id": id_name})
if eles is None or len(eles) == 0:
return None
return eles

# 通过标签名和name获取第一个元素
def get_one_by_name(soup, ele_name, name):
if soup is None:
return None
eles = soup.find_all(ele_name, {"name": name}, limit=1)
if eles is None or len(eles) == 0:
return None
return eles[0]

# 通过标签名和name获取所有元素
def get_by_name(soup, ele_name, name):
if soup is None:
return None
eles = soup.find_all(ele_name, {"name": name})
if eles is None or len(eles) == 0:
return None
return eles

# 通过标签名获取第一个元素
def get_one_by_tag(soup, ele_name):
if soup is None:
return None
eles = soup.find_all(ele_name, limit=1)
if eles is None or len(eles) == 0:
return None
return eles[0]

# 通过标签名获取所有元素
def get_by_tag(soup, ele_name):
if soup is None:
return None
eles = soup.find_all(ele_name)
if eles is None or len(eles) == 0:
return None
return eles

# 获取元素属性
def get_ele_attr(ele, attr_name):
if ele is None:
return None
atts = ele.get(attr_name)
if atts is None or len(atts) == 0:
return None
return atts

# 获取元素内部文本
def get_ele_txt(ele):
if ele is None:
return None
txt = ele.get_text()
if txt is None or len(txt) == 0:
return None
return txt


以上就是我们用到的解析html的工具类,需求相对比较简单;

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