两个字符串是变位词-LintCode

写出一个函数 anagram(s, t) 判断两个字符串是否可以通过改变字母的顺序变成一样的字符串

说明

What is Anagram?

- Two strings are anagram if they can be the same after change the order of characters.

样例

给出 s = “abcd”，t=”dcab”，返回 true.

给出 s = “ab”, t = “ab”, 返回 true.

给出 s = “ab”, t = “ac”, 返回 false.

挑战

O(n) time, O(1) extra space

#ifndef C158_H
#define C158_H
#include<iostream>
#include<string>
#include<algorithm>
using namespace std;
class Solution {
public:
/**
* @param s: The first string
* @param b: The second string
* @return true or false
*/
bool anagram(string s, string t) {
// write your code here
if (s.empty() || t.empty() || s.size() != t.size())
return false;
//将s,t按字典排序,并比较排序后的字符串是否相同
sort(s.begin(), s.end());
sort(t.begin(), t.end());
return s == t ? true : false;
}
};
#endif