PYTHON代码：根据位图间的关系，连接IBM V7000的8G BS位图

import sqlite3
import struct
cx_m = sqlite3.connect("F:\\zy\\map\\map_v2.db")
cu_m = cx_m.cursor()
BS = 256 * 1024 * 1024
bs = 256 * 1024
sDisk = []
sDisk.append("")
sDisk.append("")
sDisk.append("")
sDisk.append("")
sDisk.append(["h:\mdisk4.img", 0])
sDisk.append(["g:\mdisk5.img", 0])
sDisk.append(["i:\mdisk6.img", 0])
sDisk.append(["d:\mdisk7.img", 0])
sDisk.append(["e:\mdisk8.img", 0])
sDisk.append(["f:\mdisk9.img", 0])
for disk in sDisk[4:10]:
disk[1] = open(disk[0], 'rb')
tlist = list()
curNo,curDid,curBS =0,4,800
tlist.append([curNo,curDid,curBS])
pEnd = 0
while True:
pos = curBS * BS + 512 * 1024
f = sDisk[curDid][1]
f.seek(pos)
d = f.read(bs)
v = struct.unpack_from("Q",d,bs -8 - pEnd * 8)[0]
if v == 0:
break
if curBS == 13333 or curBS == 21088 :
vj = 160
elif curBS == 22588 or (curBS == 3861 and curDid == 7):
vj = 1600
elif curBS == 26044:
v = 39160914945
elif curBS == 6834 and curDid == 8:
v = 55357308929
elif curBS == 6866 and curDid == 8:
v = 55407631873
elif curBS == 10472 and curDid == 9:
v = 54081059329
else:
vj = 16
v1 = v-vj*512
v2 = v+vj*512
#print("v1,v2:",v1,v2)
cu_m.execute(r"select * from map_info where v_num > %d and v_num < %d and MAP_ITEM_POS < 5"%(v1,v2))
rows = cu_m.fetchall()
isbreak = False
if len(rows) == 0:
if pEnd < 7:
pEnd += 1
continue;
else:
print("len is 0:CurDid,CurBS is break", curDid, curBS)
#print(tlist)
pEnd = 0
break;
elif len(rows) > 1:
t1,t2 = rows[0][0],rows[0][1]
#print("t1,t2 is",t1,t2)
for row1 in rows:
if t1 != row1[0] or t2 != row1[1]:
print("len >1,t1,t2,row[0],row[1] is",t1,t2,row1[0],row1[1])
isbreak = True
break;
if isbreak:
print("CurDid,CurBS is break", curDid, curBS)
#        print(tlist)
break;
else:
pEnd = 0
curNo += 1
curDid = rows[0][0]
curBS = rows[0][1]
#if curDid== 9 and curBS== 7471:
#    break
tlist.append([curNo,curDid,curBS])
# if curBS == 18511 and curDid == 8:
#    break
print("the list num is",len(tlist))
print(tlist)
f1 = open("f:\\zy\\8gLIST.TXT",'w+')
for i in tlist:
f1.write("%d\t%d\t%d\n"%(i[0],i[1],i[2]))