您的位置:首页 > 其它

Sum Root to Leaf Numbers问题及解法

2017-08-12 18:08 267 查看
问题描述:

Given a binary tree containing digits from 
0-9
 only, each root-to-leaf path could represent
a number.

An example is the root-to-leaf path 
1->2->3
 which represents the number 
123
.

Find the total sum of all root-to-leaf numbers.

示例:
1
/ \
2   3


The root-to-leaf path 
1->2
 represents the number 
12
.

The root-to-leaf path 
1->3
 represents the number 
13
.

Return the sum = 12 + 13 = 
25
.

问题分析:

典型的根先序遍历问题,到结点root时,和s = s * 10 + root->val,若root是叶子节点,则总和sum = sum + s;

过程详见代码:

/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
int sumNumbers(TreeNode* root) {
int sum = 0;
sumofpath(root, sum, 0);
return sum;
}

void sumofpath(TreeNode* root,int& sum,int s)
{
if (root == NULL) return;
s = s * 10 + root->val;
if (root->left == NULL && root->right == NULL)
sum += s;
sumofpath(root->left, sum, s);
sumofpath(root->right, sum, s);

}
};
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: