shell关于sed，awk日志分割

首先是一段日志内容：

[09/Aug/2017:12:00:05 +0800]

[09/Aug/2017:12:00:08 +0800]

[09/Aug/2017:12:00:12 +0800]

[09/Aug/2017:12:00:15 +0800]

[09/Aug/2017:12:00:19 +0800]

[09/Aug/2017:12:00:57 +0800]

[09/Aug/2017:12:01:05 +0800]

[09/Aug/2017:12:01:07 +0800]

[09/Aug/2017:12:01:08 +0800]

[09/Aug/2017:12:01:09 +0800]

[09/Aug/2017:12:01:13 +0800]

[09/Aug/2017:12:02:58 +0800]

[09/Aug/2017:12:03:00 +0800]

[09/Aug/2017:12:03:04 +0800]

[09/Aug/2017:12:03:09 +0800]

[09/Aug/2017:12:03:12 +0800]

[09/Aug/2017:12:03:16 +0800]

[09/Aug/2017:12:03:19 +0800]

[09/Aug/2017:12:07:35 +0800]

[09/Aug/2017:12:07:36 +0800]

[09/Aug/2017:12:07:36 +0800]

取中间一段内容：

sed '/12:00:05/,/12:03:19/p' test -n

以一定规则分割：

awk '{print $1}' test |sed  's#\[##g'| awk -F ':' -vOFS=':' '{print $1,$2,$3}' |sed '/[0-2]$/p' -n

还可以cut -d' ' -f