顺时针打印矩阵

输入一个矩阵，按照从外向里以顺时针的顺序依次打印出每一个数字，例如，如果输入如下矩阵： 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 则依次打印出数字1,2,3,4,8,12,16,15,14,13,9,5,6,7,11,10.

没什么水平的题，不能通过的原因可能是不太细心

思路：记录矩形四个角的坐标

（x, y） (x, col-x-1)

(row-x-1, y) (row-x-1, col-x-1)

每次循环递增x和y就OK

code:

class Solution {
public:
vector<int> printMatrix(vector<vector<int> > matrix)
{
vector<int> answer;

int row= matrix.size();

if(0 == row)
{
return answer;
}

int col= matrix[0].size();

if(0 == col)
{
return answer;
}

int totalNumber= row* col;

int x= 0,y= 0;

int cutIdx= 0;

while(true)
{
for(int i= y; i<= col-x-1; ++i)
{
answer.push_back(matrix[x][i]);
if(totalNumber == answer.size())
{
return answer;
}
}

for(int i= x+1; i<= row-x-1; ++i)
{
answer.push_back(matrix[i][col-1-x]);
if(totalNumber == answer.size())
{
return answer;
}
}

for(int i= col-x-2; i>= y; --i)
{
answer.push_back(matrix[row-x-1][i]);
if(totalNumber == answer.size())
{
return answer;
}
}

for(int i= row-x-2; i>= x+1; --i)

4000
{
answer.push_back(matrix[i][y]);
if(totalNumber == answer.size())
{
return answer;
}
}

++x;
++y;
}

return answer;
}
};