UVA 10474 Where is the Marble?【vector的sort用法】
2017-08-06 22:01
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Source
点击打开链接
题意:给出两个数n和q,下面输入n个数,再依次输入q个询问,分别查找q个数在n个数中是第几大,
思路:很简单,排序加二分查找,主要目的在于熟悉一下vector的sort用法:
sort(vect.begin(), vect.end());
sort(vect.begin(), vect.end(), less<int>() );
第三个参数可以自定义,主要用于自定义类型的排序
注:
1、迭代器的函数
2、sort的参数是针对半开区间的[begin,end)
代码:
#include<stdio.h>
#include<algorithm>
#include<vector>
using namespace std;
vector<int> v;
int binary_find(int x)
{
int len=v.size();
int l=0,r=len-1;
while(l<=r)
{
int mid=(l+r)/2;
if(v[mid]==x)
{
while(v[mid-1]==v[mid]) mid--;
return mid+1;
}
else if(v[mid]<x) l=mid+1;
else r=mid-1;
}
return 0;
}
int main()
{
int n,q,x,ans,k=1;
while(scanf("%d %d",&n,&q)==2 && (n!=0 || q!=0))
{
v.clear();
for(int i=0;i<n;i++)
{
scanf("%d",&x);
v.push_back(x);
}
sort(v.begin(),v.end());
printf("CASE# %d:\n",k++);
for(int i=0;i<q;i++)
{
scanf("%d",&x);
ans=binary_find(x);
if(ans) printf("%d found at %d\n",x,ans);
else printf("%d not found\n",x);
}
}
return 0;
}
点击打开链接
题意:给出两个数n和q,下面输入n个数,再依次输入q个询问,分别查找q个数在n个数中是第几大,
思路:很简单,排序加二分查找,主要目的在于熟悉一下vector的sort用法:
sort(vect.begin(), vect.end());
sort(vect.begin(), vect.end(), less<int>() );
第三个参数可以自定义,主要用于自定义类型的排序
注:
1、迭代器的函数
begin() | 返回一个迭代器,指向第一个元素 |
end() | 返回一个迭代器,指向最后一个元素的后一个 |
代码:
#include<stdio.h>
#include<algorithm>
#include<vector>
using namespace std;
vector<int> v;
int binary_find(int x)
{
int len=v.size();
int l=0,r=len-1;
while(l<=r)
{
int mid=(l+r)/2;
if(v[mid]==x)
{
while(v[mid-1]==v[mid]) mid--;
return mid+1;
}
else if(v[mid]<x) l=mid+1;
else r=mid-1;
}
return 0;
}
int main()
{
int n,q,x,ans,k=1;
while(scanf("%d %d",&n,&q)==2 && (n!=0 || q!=0))
{
v.clear();
for(int i=0;i<n;i++)
{
scanf("%d",&x);
v.push_back(x);
}
sort(v.begin(),v.end());
printf("CASE# %d:\n",k++);
for(int i=0;i<q;i++)
{
scanf("%d",&x);
ans=binary_find(x);
if(ans) printf("%d found at %d\n",x,ans);
else printf("%d not found\n",x);
}
}
return 0;
}
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