Binary String Matching

Binary String Matching

时间限制：3000 ms  |  内存限制：65535 KB
难度：3

描述Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell how many times does A appear as a substring of B? For example, the text string B is ‘1001110110’ while the pattern string A is
‘11’, you should output 3, because the pattern A appeared at the posit

输入The first line consist only one integer N, indicates N cases follows. In each case, there are two lines, the first line gives the string A, length (A) <= 10, and the second line gives the string B, length (B) <= 1000. And
it is guaranteed that B is always longer than A.
输出For each case, output a single line consist a single integer, tells how many times do B appears as a substring of A.
样例输入

3
11
1001110110
101
110010010010001
1010
110100010101011

样例输出

3
0
3

来源网络
上传者
naonao
#include <iostream>
#include <string>
using namespace std;

int main(){
int t;
string a, b;
cin >> t;

while(t--){
cin >> a >> b;
int n = 0;
int index = b.find(a, 0);//返回从0开始找到子串在串中的位置下标
while(index != b.npos){//npos表示不存在
n++;
index = b.find(a, index + 1);
}
cout << n << endl;
}

return 0;
}