JS浮点计算问题

方法一：
加减乘除
function add(a, b) {
var c, d, e;
try {
c = a.toString().split(".")[1].length;
} catch (f) {
c = 0;
}
try {
d = b.toString().split(".")[1].length;
} catch (f) {
d = 0;
}
return e = Math.pow(10, Math.max(c, d)), (mul(a, e) + mul(b, e)) / e;
}
function sub(a, b) {
var c, d, e;
try {
c = a.toString().split(".")[1].length;
} catch (f) {
c = 0;
}
try {
d = b.toString().split(".")[1].length;
} catch (f) {
d = 0;
}
return e = Math.pow(10, Math.max(c, d)), (mul(a, e) - mul(b, e)) / e;
}
function mul(a, b) {
var c = 0,
d = a.toString(),
e = b.toString();
try {
c += d.split(".")[1].length;
} catch (f) {}
try {
c += e.split(".")[1].length;
} catch (f) {}
return Number(d.replace(".", "")) * Number(e.replace(".", "")) / Math.pow(10, c);
}
function div(a, b) {
var c, d, e = 0,
f = 0;
try {
e = a.toString().split(".")[1].length;
} catch (g) {}
try {
f = b.toString().split(".")[1].length;
} catch (g) {}
return c =
4000
Number(a.toString().replace(".", "")), d = Number(b.toString().replace(".", "")), mul(c / d, Math.pow(10, f - e));
}
方法二：

加法计算function accAdd(arg1,arg2){
var r1,r2,m;
try{r1=arg1.toString().split(".")[1].length}catch(e){r1=0}
try{r2=arg2.toString().split(".")[1].length}catch(e){r2=0}
m=Math.pow(10,Math.max(r1,r2))
return (arg1*m+arg2*m)/m
}