ZCMU新人训练赛K

K - Yet Another Story of Rock-paper-scissors

 ZOJ- 3610 Akihisa and Hideyoshi were lovers. They were sentenced to death by the FFF Inquisition. Ryou, the leader of the FFF Inquisition, promised that the winner of Rock-paper-scissors would be immune from the punishment. Being lovers, Akihisa and Hideyoshi decidedto die together with their fists clenched, which indicated rocks in the game. However, at the last moment, Akihisa chose paper and Hideyoshi chose scissors. As a result, Akihisa was punished by the FFF Inquisition and Hideyoshi survived alone.When a boy named b and a girl named g are being punished by the FFF Inquisition, they will play Rock-paper-scissors and the winner will survive. If there is a tie, then neither of they will survive. At first, they promise to choosethe same gesture x. But actually, the boy wants to win and the girl wants to lose. Of course, neither of them knows that the other one may change his/her gesture. At last, who will survive?InputThere are multiple test cases. The first line of input is an integer T ≈ 1000 indicating the number of test cases.Each test case contains three strings -- b g x. All strings consist of letters and their lengths never exceed 20. The gesture x is always one of 

"rock"

, 

"paper"

 and 

"scissors"

.<h4< dd="">OutputIf there is a tie, output 

"Nobody will survive"

. Otherwise, output 

"y will survive"

 wherey is the name of the winner.<h4< dd="">Sample Input

1
Akihisa Hideyoshi rock

Sample Output

Hideyoshi will survive

AC代码：

#include<iostream>#include<string.h>#include<cstring>#include<stdio.h>#include<string>using namespace std;int main(){        int t;        scanf("%d",&t);        while(t--)        {                string b,g,x;                cin>>b>>g>>x;                cout<<g<<" will survive"<<endl;        }        return 0;}