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leetcode 268. Missing Number

2017-07-28 16:03 417 查看
Given an array containing n distinct numbers taken from
0, 1, 2, ..., n
, find the one that is missing from the array.

For example,
Given nums =
[0, 1, 3]
return
2
.

Note:
Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity?

呵呵

class Solution {
public:
int missingNumber(vector<int>& nums) {
int sum = 0;
for (int x : nums) {
sum += x;
}
int n = nums.size();
return  n * (1 + n) / 2 - sum;
}
};
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