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sdut 1959 简单枚举类型——植物与颜色

2017-07-27 16:57 302 查看
题目链接

Problem Description

请定义具有red, orange, yellow, green, blue, violet六种颜色的枚举类型color,根据输入的颜色名称,输出以下六种植物花朵的颜色:Rose(red), Poppies(orange), Sunflower(yellow), Grass(green), Bluebells(blue), Violets(violet)。如果输入的颜色名称不在枚举类型color中,例如输入purple,请输出I don’t know about the color purple.

Input

输入数据有多行,每行有一个字符串代表颜色名称,颜色名称最多30个字符,直到文件结束为止。

Output

输出对应颜色的植物名称,例如:Bluebells are blue. 如果输入的颜色名称不在枚举类型color中,例如purple, 请输出I don’t know about the color purple.

Example Input

blue

yellow

purple

Example Output

Bluebells are blue.

Sunflower are yellow.

I don’t know about the color purple.

使用枚举类型的时候要用强制类型转换

#include<iostream>
using namespace std;
typedef enum color{
red, orange, yellow, green, blue, violet
}color;
int main(){
string s;
while(cin>>s){
int co;
if(s=="red")
co = 0;
else if(s=="orange")
co = 1;
else if(s=="yellow")
co = 2;
else if(s=="green")
co = 3;
else if(s=="blue")
co = 4;
else if(s=="violet")
co = 5;
else
co = 6;
switch((color) co){//强制类型转换为color类型
case 0:cout<<"Rose are red."<<endl;break;
case 1:cout<<"Poppies are orange."<<endl;break;
case 2:cout<<"Sunflower are yellow."<<endl;break;
case 3:cout<<"Grass are green."<<endl;break;
case 4:cout<<"Bluebells are blue."<<endl;break;
case 5:cout<<"Violets are violet."<<endl;break;
default:cout<<"I don't know about the color "<<s<<"."<<endl;break;
}
}
return 0;
}
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