hdu 6033 Add More Zero(数的位数)
2017-07-27 11:53
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题意:
求2的k次方的数的位数-1
思路:
数的位数 (int)log10(n)+1
log10(2^k)=k*log10(2),取个int就行了
#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <algorithm>
#include <math.h>
using namespace std;
int main()
{
int a,ans,cas=1;
while(scanf("%d",&a)!=-1)
{
ans=(int)(log10(2.0)*a);
printf("Case #%d: %d\n",cas++,ans);
}
return 0;
}
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