2个线程模拟卖火车票

2个线程模拟卖火车票

最近在看关于进程线程的知识点，然后手动敲一遍代码，但是发现一个问题，运行结果的第一行不知道是什么情况。。先记录下来，供以后继续学习的参考吧

#include <iostream>
#include <windows.h>
using namespace std;

//2个线程卖火车票的小程序
DWORD WINAPI Fun1Proc(LPVOID lpParameter); //thread data
DWORD WINAPI Fun2Proc(LPVOID lpParameter); //thread data

int index=0;
int tickets=10;
HANDLE hMutex;
int main()
{
HANDLE hThread1;
HANDLE hThread2;
//创建线程
hThread1=CreateThread(NULL, 0, Fun1Proc, NULL, 0, NULL);
hThread2=CreateThread(NULL, 0, Fun2Proc, NULL, 0, NULL);
CloseHandle(hThread1);
CloseHandle(hThread2);
//创建互斥对象
hMutex=CreateMutex(NULL,TRUE,"tickets");
if(hMutex)
{
if(ERROR_ALREADY_EXISTS==GetLastError())
{
cout<<"only one instance can run!"<<endl;
return 0;
}
}
WaitForSingleObject(hMutex,INFINITE);
ReleaseMutex(hMutex);
ReleaseMutex(hMutex);
Sleep(4000);
return 0;
}

//线程1的入口函数
DWORD WINAPI Fun1Proc(LPVOID lpParameter)//thread data
{
while(true)
{
ReleaseMutex(hMutex);
WaitForSingleObject(hMutex,INFINITE);
if(tickets>0)
{
Sleep(1);
cout<<"thread1 sell tickets:"<<tickets--<<endl;
}
else
break;
ReleaseMutex(hMutex);
}
return 0;
}

//线程2的入口函数
DWORD WINAPI Fun2Proc(LPVOID lpParameter)//thread data
{
while(true)
{
ReleaseMutex(hMutex);
WaitForSingleObject(hMutex,INFINITE);
if(tickets>0)
{
Sleep(1);
cout<<"thread2 sell tickets:"<<tickets--<<endl;
}
else
break;
ReleaseMutex(hMutex);
}
return 0;
}

这个问题等自己解决后再来更新想法吧