2017 Multi-University Training Contest - Team 1 1011&&HDU 6043 KazaQ's Socks【规律题,数学,水】
2017-07-26 09:32
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KazaQ's Socks
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 338 Accepted Submission(s): 212
![](https://oscdn.geek-share.com/Uploads/Images/Content/201707/5aa70248bbe2e8052b9974866ca81f66.png)
[align=left]Sample Input[/align]
3 7 3 6 4 9
[align=left]Sample Output[/align]
Case #1: 3 Case #2: 1 Case #3: 2
[align=left]Source[/align]
2017 Multi-University Training Contest - Team 1
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=6043
分析:
![](https://oscdn.geek-share.com/Uploads/Images/Content/201707/5ab15e69ed7b355f86aa93e1637bb3df.png)
然后分别去判断即可!详细请看代码。
下面给出AC代码:
#include <bits/stdc++.h> using namespace std; typedef long long ll; int main() { ll n,m; ll p=1; while(scanf("%lld%lld",&n,&m)!=EOF) { printf("Case #%lld: ",p++); if(m<=n) { printf("%lld\n",m); continue; } ll c=m-n; if(c%(2*(n-1))==0) { printf("%lld\n",n); continue; } if(c%(2*(n-1))<=n-1) printf("%lld\n",c%(2*(n-1))); else { ll k=c%(2*(n-1))%(n-1); printf("%lld\n",k); } } return 0; }
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