LeetCode 58. Length of Last Word
2017-07-25 00:59
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int lengthOfLastWord(char* s) { int count=0; //长度为0的情况 if(s==NULL || strlen(s)==0){ return 0; }else{ for (int i = strlen(s)-1; i >=0 ; i--) { //空格的情况 一开始边界就是空格不处理continua即可 如果是第一个单词数出来了也就是记录不为0那么继续处理。 if (' '== s[i]){ if(count>0) { break; } continue; //尾部出现非字母即 空格 }else { count++; //遇到非空格即字母开始 } } return count; } }
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