Return array from functions in C++

C++ does not allow to return an entire array as an argument to a function. However, you can return a pointer to an array by specifying the array's name without an index.

If you want to return a single-dimension array from a function, you would have to declare a function returning a pointer as in the following example:

int
* myFunction()
{

.

.

.

}

Second point to remember is that C++ does not advocate to return the address of a local variable to outside of the function so you would have to define the local variable as static variable.

Now, consider the following function, which will generate 10 random numbers and return them using an array and call this function as follows:

#include
<iostream>

#include
<ctime>

 

using
namespace std;

 

// function to generate and retrun random numbers.

int
* getRandom(
)
{

static
int r[10];

 

// set the seed

srand(
(unsigned)time( NULL )
);

    
 

for
(int i =
0; i <
10;
++i)
{

r[i]
= rand();

cout << r[i]
<< endl;

}

 

return r;

}

 

// main function to call above defined function.

int main ()
{

// a pointer to an int.

int
*p;

 

p = getRandom();

    
 

for
(
int i =
0; i <
10; i++
)
{

cout <<
"*(p + "
<< i <<
") : ";

cout <<
*(p + i)
<< endl;

}

 

return
0;

}

When the above code is compiled together and executed, it produces result something as follows:

624723190

1468735695

807113585

976495677

613357504

1377296355

1530315259

1778906708

1820354158

667126415

*(p + 0) : 624723190

*(p + 1) : 1468735695

*(p + 2) : 807113585

*(p + 3) : 976495677

*(p + 4) : 613357504

*(p + 5) : 1377296355

*(p + 6) : 1530315259

*(p + 7) : 1778906708

*(p + 8) : 1820354158

*(p + 9) : 667126415