leetcode 27. Remove Element
2017-07-21 19:37
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Given an array and a value, remove all instances of that value in place and return the new length.
Do not allocate extra space for another array, you must do this in place with constant memory.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
Example:
Given input array nums =
Your function should return length = 2, with the first two elements of nums being 2.
解:就是在数组前面放不同于val的值即可
class Solution {
public:
int removeElement(vector<int>& nums, int val) {
int len = 0;
for(int i = 0; i < nums.size(); ++i){
if(nums[i] != val){
nums[len] = nums[i];
len++;
}
}
return len;
}
};
Do not allocate extra space for another array, you must do this in place with constant memory.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
Example:
Given input array nums =
[3,2,2,3], val =
3
Your function should return length = 2, with the first two elements of nums being 2.
解:就是在数组前面放不同于val的值即可
class Solution {
public:
int removeElement(vector<int>& nums, int val) {
int len = 0;
for(int i = 0; i < nums.size(); ++i){
if(nums[i] != val){
nums[len] = nums[i];
len++;
}
}
return len;
}
};
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