Degug: QmlApplicationEngine failed to load component
2017-07-19 16:53
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我在把c++类注册成qml可用时遇到这个问题
qmlRegisterType 是一个可以将C++实现的类在QML中调用的,连接C++和QML的一个工具
首先来看QtAssistant的介绍
int qmlRegisterType(const char * uri, int versionMajor, int versionMinor, const char * qmlName)
This template function registers the C++ type in the QML system with the name qmlName, in the library imported from uri having the version number composed from versionMajor and versionMinor.
可以看到qmlRegisterType里总共4个参数,第一个参数* uri指的是QML中import后的内容,相当于头文件名,第二个第三个参数分别是主次版本号,第四个指的是QML中类的名字。
来看这一句
4000
第四个QML的类名首字母一定要大写!!!!!!qmlRegisterType<serialhandler>("Serial", 1, 0, "Serialhandler"); //这样就好了,唉 ~。~
.qml引用
int main(int argc, char *argv[])
{
QCoreApplication::setAttribute(Qt::AA_EnableHighDpiScaling);
QGuiApplication app(argc, argv);
qmlRegisterType<serialhandler>("Serial", 1, 0, "serialhandler");
QQmlApplicationEngine engine;
engine.load(QUrl(QLatin1String("qrc:/main.qml")));
if (engine.rootObjects().isEmpty())
return -1;
return app.exec();
}
qmlRegisterType 是一个可以将C++实现的类在QML中调用的,连接C++和QML的一个工具
首先来看QtAssistant的介绍
int qmlRegisterType(const char * uri, int versionMajor, int versionMinor, const char * qmlName)
This template function registers the C++ type in the QML system with the name qmlName, in the library imported from uri having the version number composed from versionMajor and versionMinor.
可以看到qmlRegisterType里总共4个参数,第一个参数* uri指的是QML中import后的内容,相当于头文件名,第二个第三个参数分别是主次版本号,第四个指的是QML中类的名字。
来看这一句
4000
qmlRegisterType<serialhandler>("Serial", 1, 0, "serialhandler");
第四个QML的类名首字母一定要大写!!!!!!qmlRegisterType<serialhandler>("Serial", 1, 0, "Serialhandler"); //这样就好了,唉 ~。~
.qml引用
import Serial 1.0
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