leetcode 11 -- Container With Most Water
2017-07-19 14:43
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题目
Given n non-negative integers a1, a2, …, an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.
Note: You may not slant the container.
题意
从给定数组a[i]中找出 i。j使得 abs(j-i)*min(a[i],a[j])值最大
思路
刚開始使用两重循环,o(n^2),超时。改为贪心思想,每次仅仅尝试有可能更优的解。终于遍历完后,时间复杂度o(n);
详细步骤 设i位于序列首。j位于序列尾。则若a[i]
Given n non-negative integers a1, a2, …, an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.
Note: You may not slant the container.
题意
从给定数组a[i]中找出 i。j使得 abs(j-i)*min(a[i],a[j])值最大
思路
刚開始使用两重循环,o(n^2),超时。改为贪心思想,每次仅仅尝试有可能更优的解。终于遍历完后,时间复杂度o(n);
详细步骤 设i位于序列首。j位于序列尾。则若a[i]
int maxArea(int* height, int heightSize) { int max=0,f,a,i=0,j=heightSize-1; while(i<j) { f=height[i]<height[j]? 1:0; if(f) { a=(j-i)*height[i]; i++; } else { a=(j-i)*height[j]; j--; } if(a>max) { max=a; } } return max; }
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