POJ 3128 Leonardo's Notebook 笔记
2017-07-17 19:50
323 查看
给出一串由26个字母组成的字符串,判断能否由ABC...XYZ经过两次替换加密得到。
相关文章推荐
- poj 3128 Leonardo's Notebook (置换)
- 【POJ 3128】Leonardo's Notebook
- POJ 题目3128Leonardo's Notebook(置换的平方)
- poj 3128 Leonardo's Notebook(置换的幂)
- poj 3128 Leonardo's Notebook(置换群的分数幂运算)
- [ACM] poj 3128 Leonardo's Notebook (置换群,循环节)
- poj 3128 Leonardo's Notebook(置换的幂)
- [ACM] poj 3128 Leonardo's Notebook (置换群,循环节)
- POJ 3128 Leonardo's Notebook
- [ACM] poj 3128 Leonardo's Notebook (置换群,循环节)
- POJ 3128 Leonardo's Notebook(置换)
- poj 3128 Leonardo's Notebook (置换群)
- POJ-3128 Leonardo's Notebook 置换群分数幂
- Leonardo's Notebook POJ - 3128(置换群的开方判断)
- POJ 3128 Leonardo's Notebook [置换群]
- POJ 2010 Moo University - Financial Aid 笔记
- POJ 1782 Run Length Encoding 笔记
- poj 3128
- POJ 1823 Hotel 笔记
- POJ 3233 Matrix Power Series 笔记