[LeetCode] 561. Array Partition I
2017-07-12 11:49
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Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), …, (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible.
Example 1:
Note:
n is a positive integer, which is in the range of [1, 10000].
All the integers in the array will be in the range of [-10000, 10000].
Example 1:
Input: [1,4,3,2] Output: 4 Explanation: n is 2, and the maximum sum of pairs is 4 = min(1, 2) + min(3, 4).
Note:
n is a positive integer, which is in the range of [1, 10000].
All the integers in the array will be in the range of [-10000, 10000].
class Solution { public: int arrayPairSum(vector<int>& nums) { const int n = nums.size() / 2; sort(nums.begin(), nums.end()); int sum = 0; for (int i = 0; i < n; i++) sum += nums[2 * i]; return sum; } };
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