您的位置:首页 > 编程语言 > Lua

150. Evaluate Reverse Polish Notation

2017-07-07 20:50 232 查看
Evaluate the value of an arithmetic expression in Reverse Polish Notation.

Valid operators are +, -, *, /. Each operand may be an integer or another expression.

Some examples:

["2", "1", "+", "3", "*"] -> ((2 + 1) * 3) -> 9
["4", "13", "5", "/", "+"] -> (4 + (13 / 5)) -> 6


一个栈的案例:

int evalRPN(vector<string>& tokens) {
if (tokens.size() == 0)return 0;
stack<int> res;
int sum = 0;
for (int i = 0; i < tokens.size(); i++){
if (tokens[i] != "+" && tokens[i] != "-" && tokens[i] != "*" && tokens[i] != "/")res.push(stoi(tokens[i]));
else{
int temp2 = res.top(); res.pop();
int temp1 = res.top(); res.pop();
if (tokens[i] == "+") res.push(temp1 + temp2);
else if (tokens[i] == "-") res.push(temp1 - temp2);
else if (tokens[i] == "*") res.push(temp1 * temp2);
else if (tokens[i] == "/") res.push(temp1 / temp2);
}
}
return res.top();
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: