输出 n 阶实心菱形 占2*n-1行

#include <iostream>
using namespace std;

int main(){
int n;
cin >> n;
for (int i=1;i<=n;i++)
{
for (int j=1;j<=(2*n-1);j++)
{
if (j>n-i && j<n+i)
{
cout<<"*";
}
else
{
cout<<" ";
}
}
cout<<endl;
}
for (int i=n-1;i>= 1;i--)
{
for (int j=1;j<=(2*n-1);j++)
{
if (j>n-i && j<n+i)
{
cout<<"*";
}
else
{
cout<<" ";
}
}
cout<<endl;
}
system("pause");
return 0;
}