Tomcat -- 多个Context启动冲突的问题解决

启动Tomcat时，如果部署多个Web应用，可能会看到如下异常信息：

Exception sending context initialized event to listener instance of class org.springframework.web.util.Log4jConfigListener

Java.lang.IllegalStateException: Web app root system property already set to different value: ‘webapp.root’ = [/Users/work/apache-tomcat-7.0.52/webapps/project1/] instead of [/Users/work/apache-tomcat-7.0.52/webapps/project2/] - Choose unique values for the ‘webAppRootKey’ context-param in your web.xml files!

假设有两个web应用：project1和project2

project1所在目录为：/Users/work/apache-tomcat-7.0.52/webapps/project1

project2所在目录为：/Users/work/apache-tomcat-7.0.52/webapps/project2

解决方法为：修改project1和project2中的web.xml文件

①修改project1的web.xml文件：

<context-param>
<param-name>webAppRootKey</param-name>
<param-value>project1</param-value>
</context-param>

②修改project2的web.xml文件：

<context-param>
<param-name>webAppRootKey</param-name>
<param-value>project2</param-value>
</context-param>

在Java代码中，可以通过如下方法获取webapp.root：

①获取project1的webapp.root

System.getProperty("project1");

输出为：

/Users/work/apache-tomcat-7.0.52/webapps/project1

②获取project2的webapp.root

System.getProperty("project2");

输出为：

/Users/work/apache-tomcat-7.0.52/webapps/project2