Leetcode Path Sum II
2017-06-29 10:05
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Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum.
For example:
Given the below binary tree and
return
代码如下:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<vector<int>> pathSum(TreeNode* root, int sum) {
vector<vector<int>> result;
vector<int> temp;
pathSum(result,temp,root,sum);
return result;
}
void pathSum(vector<vector<int>>& result,vector<int>& temp,TreeNode* root,int sum)
{
if(root == NULL) return;
if(root->left == NULL && root->right == NULL && root->val == sum)
{
temp.push_back(root->val);
result.push_back(temp);
temp.pop_back();
return;
}
temp.push_back(root->val);
pathSum(result,temp,root->left,sum-root->val);
pathSum(result,temp,root->right,sum-root->val);
temp.pop_back();
}
};
For example:
Given the below binary tree and
sum = 22,
5 / \ 4 8 / / \ 11 13 4 / \ / \ 7 2 5 1
return
[ [5,4,11,2], [5,8,4,5] ]
代码如下:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<vector<int>> pathSum(TreeNode* root, int sum) {
vector<vector<int>> result;
vector<int> temp;
pathSum(result,temp,root,sum);
return result;
}
void pathSum(vector<vector<int>>& result,vector<int>& temp,TreeNode* root,int sum)
{
if(root == NULL) return;
if(root->left == NULL && root->right == NULL && root->val == sum)
{
temp.push_back(root->val);
result.push_back(temp);
temp.pop_back();
return;
}
temp.push_back(root->val);
pathSum(result,temp,root->left,sum-root->val);
pathSum(result,temp,root->right,sum-root->val);
temp.pop_back();
}
};
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