45-Jump Game II
2017-06-22 14:42
441 查看
题目
Given an array of non-negative integers, you are initially positioned at the first index of the array.Each element in the array represents your maximum jump length at that position.
Your goal is to reach the last index in the minimum number of jumps.
For example:
Given array A = [2,3,1,1,4]
The minimum number of jumps to reach the last index is 2. (Jump 1 step from index 0 to 1, then 3 steps to the last index.)
分析
关联问题 55-Jump Game贪心算法
- currJump 当前的跳数
- currRange 当前跳数所能达到的最大范围
- iRange 在i 位置时所能达到的最大范围
实现
class Solution { public: int jump(vector<int>& nums) { int len = nums.size(); if (len == 0) return 0; int currJump=0, currRange=0, iRange = 0; for (int i = 0; i < len; i++) { //如果当前跳数所达到的最大范围不超过i,那么需要跳数增加 if (currRange < i) { currJump++; currRange = iRange; } iRange = max(iRange, nums[i] + i); } return currJump; } };
相关文章推荐
- 45. Jump Game II
- LeetCode 45 --- Jump Game II
- 45. Jump Game II
- Leetcode 45 Jump Game II
- leetCode #45 Jump Game II 贪心
- [LeetCode]45 Jump Game II
- 45. Jump Game II
- [LeetCode#55, 45]Jump Game, Jump Game II
- LeetCode (45) Jump Game II
- 45. Jump Game II
- 45-Jump Game II
- 45. Jump Game II
- LeetCode (45) Jump Game II
- 45. Jump Game II
- leetcode45 Jump Game II
- 45. Jump Game II
- LeetCode 45 - Jump Game II
- 45. Jump Game II
- Leetcode45 Jump Game II
- 45. Jump Game II