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根据map中的key或者value值进行排序

2017-06-22 10:38 441 查看
1.根据key值进行排序
import java.util.Comparator;
import java.util.Iterator;
import java.util.Map;
import java.util.Set;
import java.util.TreeMap;
public class TreeMapTest {
public static void main(String[] args) {
Map<String, String> map = new TreeMap<String, String>(
new Comparator<String>() {
public int compare(String obj1, String obj2) {
// 降序排序
return obj2.compareTo(obj1);
}
});
map.put("b", "ccccc");
map.put("d", "aaaaa");
map.put("c", "bbbbb");
map.put("a", "ddddd");
        Set<String> keySet = map.keySet();
        Iterator<String> iter = keySet.iterator();
        while (iter.hasNext()) {
            String key = iter.next();
            System.out.println(key + ":" + map.get(key));
        }
    }
}
运行结果:
d:aaaaa
c:bbbbb
b:ccccc
a:ddddd
2.对value进行排序
import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.List;
import java.util.Map;
import java.util.Map.Entry;
import java.util.TreeMap;
public class TreeMapTest {
public static void main(String[] args) {
        Map<String, String> map = new TreeMap<String, String>();
map.put("a", "ddddd");
map.put("c", "bbbbb");
map.put("d", "aaaaa");
map.put("b", "ccccc");
        //这里将map.entrySet()转换成list
        List<Map.Entry<String,String>> list = new ArrayList<Map.Entry<String,String>>(map.entrySet());
        //然后通过比较器来实现排序
        Collections.sort(list,new Comparator<Map.Entry<String,String>>() {
            //升序排序
            public int compare(Entry<String, String> o1,
                    Entry<String, String> o2) {
                return o1.getValue().compareTo(o2.getValue());
            }
        });
        for(Map.Entry<String,String> mapping:list){
               System.out.println(mapping.getKey()+":"+mapping.getValue());
          }
    }
}
运行结果如下:
d:aaaaa
c:bbbbb
b:ccccc
a:ddddd
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