【leetcode-shell】Tenth Line
2017-06-21 15:01
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随便找了一个shell脚本的题目。
打印出第十行的内容。
解法一：循环，不过效率最差，排在了最后# Read from the file file.txt and output the tenth line to stdout.
#!/bin/bash
declare count=0
cat file.txt | while read line
do
if [ $count = 9 ];then
echo $line
exit 0
fi
let count=$count+1
done
解法二：sed，最快速，也最简洁
# Read from the file file.txt and output the tenth line to stdout.
#!/bin/bash
sed -n 10p file.txt
打印出第十行的内容。
解法一：循环，不过效率最差，排在了最后# Read from the file file.txt and output the tenth line to stdout.
#!/bin/bash
declare count=0
cat file.txt | while read line
do
if [ $count = 9 ];then
echo $line
exit 0
fi
let count=$count+1
done
解法二：sed，最快速，也最简洁
# Read from the file file.txt and output the tenth line to stdout.
#!/bin/bash
sed -n 10p file.txt
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