poj 2683 Ohgas' Fortune 利率计算
2017-06-17 12:57
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水题。
代码:
代码:
//poj 2683 //sep9 #include <iostream> using namespace std; int main() { int cases; scanf("%d",&cases); while(cases--){ int fund,year,op,ans=-1; scanf("%d%d%d",&fund,&year,&op); while(op--){ int A,B,flag,charge; double rate; scanf("%d%lf%d",&flag,&rate,&charge); A=fund; if(flag==1){ for(int i=0;i<year;++i){ B=(int)A*rate; A=A+B-charge; } }else{ int cumulative=0; for(int i=0;i<year;++i){ B=(int)A*rate; A-=charge; cumulative+=B; } A+=cumulative; } ans=max(ans,A); } printf("%d\n",ans); } return 0; }
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