JS-获取url中的参数值
2017-06-16 10:37
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function getParam(param) { var url = location.search; //获取url中"?"符后的字串 var theRequest = new Object(); if (url.indexOf("?") != -1) { var str = url.substr(1); strs = str.split("&"); for(var i = 0; i < strs.length; i ++) { theRequest[strs[i].split("=")[0]]=strs[i].split("=")[1]; } } return theRequest[param]; }
代入参数名
返回参数值